20v^2-13v=5

Solution for 20v^2-13v=5 equation:

20v^2-13v=5

We move all terms to the left:

20v^2-13v-(5)=0

a = 20; b = -13; c = -5;
Δ = b2-4ac
Δ = -132-4·20·(-5)
Δ = 569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{569}}{2*20}=\frac{13-\sqrt{569}}{40}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{569}}{2*20}=\frac{13+\sqrt{569}}{40}
$